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17-09-2025 Ex01a

Snippet info

Language

Python

Visibility

public

Author

kwahmail

Created

2025-09-17T11:52:56.571702Z

Updated

2025-09-17T12:55:55.383371Z

expression_result=(7-4)+(((3*6)/(2**2))%5)
expression_result=(((10+(3*2))<20) and ((15% 4)== 3)) or (not ((5-(3*2))>0
result = (not ((10 // 3) == 3)) or (((8 % 3)+1) ==3) and (7 | 2) >5)
result4 = (5+3) if ((2**3)>7) else ((4*6) if (7<8) else 5-(10/2)))
result2 = ((10>5) and (((3*3)+1) <=10)) or ((not (5!=5)) and (4*2))
result1 =3+5**2&15|2**3 if 8% 3>1 else 1 ^ 7 & 4
print(expression_result)

#leapyear : year is muliple of 4 and not multiple of 100 or year is multiple of 400
year = 2008
if (year % 4 == 0 and year % 100 !+0):
    print( True)
elif(year % 400 ==0):
    print(True)
else:
    print(False)
    
print((year % 4 == 0 and year % 100 !=0) or (year % 400 ==0))

x=True if (year % 4 == 0 and year % 100 !=0) else if year % 400 == 0 else
INFO