permutation
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import math
def permutation(n, m):
l = list(range(1,n+1))
result = []
for i in range(1,n-1):
a = m // math.factorial(n-i) #商
#b = m % math.factorial(n-i) #余数
result.append(l[a])
l.remove(l[a])
if m % 2 == 1:
result.extend([l[1], l[0]])
else:
result.extend(l)
return result
#print(permutation(3, 0)) #[1, 2, 3]
for j in range(1, math.factorial(3)+1):
print(f"m={j}, 对应的排列为：{permutation(3, j-1)}")
Python
INFO