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leap year self ex

Snippet info

Language

Python

Visibility

public

Author

miffyying621

Created

2025-04-07T08:30:47.823391Z

Updated

2025-04-07T08:33:25.32236Z

def checkleap(year):
   return year % 4==0 and not year %100==0 or year %400==0
print(checkleap(2020))


def checkleap(year):
    return (year %4 ==0 and year %100 !=0) or year %400==0
print (checkleap (2020))

#def is_leap_year(year):
    #return (year % 4 == 0 and year % 100 != 0) or (year % 400 == 0)
    

    
#year = int(input("Enter a year: "))
#if (year % 4 == 0 and year % 100 != 0) or (year % 400 == 0):
 #   print(f"{year} is a leap year.")
#else:
 #   print(f"{year} is not a leap year.")
    
year = int(input(2024))

if year % 4 == 0:
  if year % 400 == 0:
    print ("Leap year")
  elif year % 100 == 0:
     print ("Not leap year")
  else:
    print ("Leap year")
else:
  print ("Not leap year")
INFO