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#leapyear:year is multiple of 4 and not mulitple of 100 or
#year is multiple of 400
def checkleap(year):
    return year % 4==0 and not year % 100==0 or year % 400==0 
print (checkleap(2024))
x = 0 or None or [] or {}or '' or False
x = 1 or True and {"name": "john"} and [1] and (1,)
print(x)
try:
 
 
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Snippet Metadata
Owner	skyhui0001
Created	1 month ago
Modified	1 month ago
Visibility	Public