#x=7-4+3*6/(2**2)%5 #ans is true #if "and" appear,the first equaltion is important #X = (((10+(3*2)<20) and ((15 % 4))==3)) or not n 5 - (3*2)>0 #x= [1,2,3] #y=1,2,3 #print(x[2],x[-1]) #print(y[2],y[-1]) #x[2]=4 #y[2]=4 x= [1,2,3] y=1,2,3 print(x[2],x[-2]) print(y[2],y[-3]) print(0.5-0.4) def a(): x=1 y=2 print(x,y) print(a())