Reverse Integer

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LanguageRuby
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def reverse(x) arr = x.to_s.split("") rev = [] index = 1 arr.each do |a| if a == "-" && rev.length == 0 rev << a next end break if a == 0 && (rev.length - 1 == arr.length) rev[arr.length - index] = a index += 1 end rev.join.to_i end puts(reverse(-123))
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