#include <stdio.h> main() { int a = 20; int b = 10; int c = 15; int d = 5; int e; e = (a + b) * c / d; // ( 30 * 15 ) / 5 printf("(a + b) * c / d 的值是 %d\n", e ); e = ((a + b) * c) / d; // (30 * 15 ) / 5 printf("((a + b) * c) / d 的值是 %d\n" , e ); e = (a + b) * (c / d); // (30) * (15/5) printf("(a + b) * (c / d) 的值是 %d\n", e ); e = a + (b * c) / d; // 20 + (150/5) printf("a + (b * c) / d 的值是 %d\n" , e ); return 0; }