Return true if element exists in second array
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const array1 = ['a', 'b', 'c', 'x'];
const array2 = ['z', 'y', '1'];
function containsCommonItem2(arr1, arr2) {
// loop through first array and create object where properties === items in the array
// can we assume always 2 params?
let map = {};
for (let i=0; i < arr1.length; i++) {
if(!map[arr1[i]]) {
const item = arr1[i];
map[item] = true;
}
}
console.log(map);
// loop through second array and check if item in second array exists on created object.
for (let j=0; j < arr2.length; j++) {
if (map[arr2[j]]) {
return true;
}
}
return false
}
//console.log(containsCommonItem2(array1,array2));
//-------------------------------------------------------
//-------------------------------------------------------
function containsCommonItem3(arr1, arr2)
{
return arr1.some(item => arr2.includes(item));
}
console.log(containsCommonItem3(array1,array2));
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