const array1 = ['a', 'b', 'c', 'x'];
const array2 = ['z', 'y', 'a'];
function containsCommonItem2(arr1, arr2) {
// loop through 1st array and screate an object where properties === items in the array
let map = {};
for(let i=0; i<arr1.length; i++) {
if(!map[arr1[i]]) {
// let us make a map with items
const item = arr1[i];
// so that
map[item] = true;
}
}
// loop through 2nd array and check if item in 2nd array exists on created object
for(let j=0; j<arr2.length; j++) {
if(map[arr2[j]]) {
return true;
}
}
return false;
}
// O(a+b) Time Complexity
// O(a) Space Complexity
containsCommonItem2(array1, array2)
function containsCommonItem3(arr1, arr2) {
return arr1.some(item => arr2.includes(item));
}
containsCommonItem3(array1, array2)
