union and intersection
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let arr1 = [2, 5, 6]
let arr2 = [4, 6, 8, 10]
const unionAndIntersection = ( arr1 , arr2 ) => {
console.log("hello")
let union = []
let intersection = []
if(arr1.length > arr2.length){
union = arr1
for (let i=0 ; i< arr2.length ; i++){
if(arr1.includes(arr2[i])){
intersection.push(arr2[i])
}
else{
union.push(arr2[i])
}
}
}
if(arr2.length >= arr1.length){
union = arr2
for (let i=0 ; i< arr1.length ; i++){
if(arr2.includes(arr1[i])){
intersection.push(arr1[i])
}
else{
union.push(arr1[i])
}
}
}
union.sort((a,b)=> a-b)
console.log("UNION", union)
console.log("INTERSECTION", intersection)
}
unionAndIntersection(arr1, arr2)
// let objectToBeFound = {
// string1: true,
// string2: true,
// string3: true,
// string4: true,
// }
// console.log(objectToBeFound["string7"])
JavaScript
INFO