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test_parse_url

Snippet info

Language

Php

Visibility

public

Author

fenghestudio

Created

2019-09-12T02:00:15Z

Updated

2019-09-12T02:00:15Z

<?php

$url = '//www.example.com/path?googleguy=googley';

// 在 5.4.7 之前这会输出路径 "//www.example.com/path"
var_dump(parse_url($url));

?>
INFO