3

#include <iostream>
using namespace std;


int main() {
    int n, n1, n2, n3, n4, n5;
    for (n=10000; n<100000; n++)
    {
        n1=n/10000;
        n2=n%10000/1000;
        n3=n%10000%1000/100;
        n4=n%10000%1000%100/10;
        n5=n%10000%1000%100%10;
     
        if ((n1*n3*n5)%2==0){
            cout<<n<<" ";
        }
    }
    return 0;
}