Find number that appears only once.

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class Main { public static void main(String[] args) { int[] arr = { 5, 5, 4, 8, 4, 5, 8, 9, 4, 8 }; System.out.print("Input Matrix : " ); for (int i = 0; i < arr.length; i++) System.out.print(arr[i] + " " ); Main solution = new Main(); System.out.println("\n\nThe number which occured only once is: " + solution.findRequiredNum(arr, 3)); } public int findRequiredNum(int arr[], int n) { int countSetBit[] = new int[32]; for (int i = 0; i < arr.length; i++) { for (int k = 0; k < 32; k++) { int kthSetBit = 1 << k; if ((arr[i] & kthSetBit) == kthSetBit) countSetBit[k]++; } } int occurredOnce = 0; for (int i = 0; i < 32; i++) { countSetBit[i] = countSetBit[i] % n; if (countSetBit[i] == 1) occurredOnce = occurredOnce | (1 << i); } return occurredOnce; } }
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