perfect number

#include <iostream>
using namespace std;

int main() {
    for (int x=1; x<=10000;x++){
        int summ=0;
        for(int i=1;i<x;i++){
            if(x%i==0) summ=summ+i;
        }
        if(summ==x) cout<<x<<" ";
    }
    return 0;
}