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Elixir_FizzBuzz_Solution

Snippet info

Language

Elixir

Visibility

public

Author

pell

Created

2016-04-26T18:28:37Z

Updated

2016-04-27T08:46:15Z

defmodule FizzBuzz do

    def say(number) do
        
        cond do
            rem(number, 15) == 0 -> "FizzBuzz"
            rem(number, 3) == 0 -> "Fizz"
            rem(number, 5) == 0 -> "Buzz"        
            number -> Integer.to_string(number)
        end
        
    end

end

for n <- 1..20, do: IO.puts FizzBuzz.say(n)

ExUnit.start()

defmodule FizzBuzzTest do
  use ExUnit.Case

  test "1 is 1" do
    assert "1" == FizzBuzz.say(1)
  end
  
  test "3 is Fizz" do
    assert "Fizz" == FizzBuzz.say(3)
  end
  
  test "5 is Buzz" do
    assert "Buzz" == FizzBuzz.say(5)
  end
  
  test "15 is FizzBuzz" do
    assert "FizzBuzz" == FizzBuzz.say(15)
  end

end
INFO